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**Quadratic Equations - Complete the Square**

**Introduction by Example**** · ****General
Complete the Squares Method**** · Examples · Algebra
Index · ****Recommended Books**

One way to deal with quadratic equations is completing the square, where one takes an equation that does not quite resolve into a nice squared linear factor, such as

The method simply states that one makes it look like a perfect square on one side by adding an appropriate constant to both sides (in this case add 1 to both sides)

This equation is then factored in a straightforward way,

and the solutions are found by simply taking the square root of both sides:

Clearly these would be difficult to find by guessing. Also, note that there is a +/-
symbol, indicating that there are two roots, one using the + sign and the other using the
– sign. This is typical of quadratics. Since a quadratic is also known as a **second-degree
polynomial**, it can have at most two distinct roots (which do not have to be real
numbers, more on this later).

**General Complete the Squares
Method**

To find the general method of completing the square, note that we can always start with an equation like

Since

we should examine the square term

Subtracting yields a difference of

Therefore, adding this term to both sides of our beginning equation above yields

or,

Examples · Example 1 · Example 2 · Example 3 · Example 4 · Example 5 · Example 6

Solve the following equation for x

Solution

Here b = 16, b/2 = 8 and k = -8 like so:

Plugging these numbers into our formula above gives

or

Solve the following equation for x

Solution

First, divide the entire equation by 9:

Now, b = -4, b/2 = -2 and k = 3, so plugging this into the formula gives

Solve for x

Solution

Multiply by 2 to get rid of the coefficient in front of the first term

then subtract 4 from both sides to put the equation in a form as above

Now it is apparent that b = 4, b/2 = 2 and k = -4. Plug these into the complete the square formula to get

In other words,

This equation has only one repeated root. Remember that quadratics have at most two distinct roots.

Solve for x

Solution

Even though this equation can be solved by simpler means, we are looking at using the complete the square formula, so add 1 to both sides and put in a "ghost" or zero term to hold the "x" place:

Now that the equation is in standard form, we have b = 0, b/2 = 0 and k = 1. Plugging these values into the equation yields

This is as expected, and verifies that complete the square agrees with common sense.

Solve for x

Solution

Here b = -2, b/2 = -1 and k = -5. Plugging these in gives

so that

and

This solution is interesting in that the two solutions are complex conjugates.

Solve for x

Solution

This problem is best solved by a substitution: let u = x + 2 so that x = u – 2. Putting these into either side of the equation yields

This puts the equation in standard form with b = -1, b/2 = -1/2 and k = -4, so, completing the square,

A little algebra yields

Don’t forget that we need to find x, not u, so we have one more step to go:

While this method might at first seem a bit complicated, it has the advantage of being very clean, avoids multiplying out a quadratic term and combining with the rest of the equation, then putting the whole thing into standard form. Substitutions like this become very important in more advanced math, and are well worth learning. Normally, they really do simplify calculations, and also often allow them to be checked for errors much more easily.

College Algebra (Schaum's Outlines)

The classic algebra problem book - very light on theory, plenty of problems with full solutions, more problems with answers

Schaum's Easy Outline: College Algebra

A simplified and updated version of the classic Schaum's Outline. Not as complete as the previous book, but enough for most students